Ndm hgc 2018 - 2019
dung 6n tQp HKI
NQi
-TU6ru
HgC rcY I TOAN 7
NQI DUNC O^I TAP
LY THUYET
A.
I/ Dai s6:
nhu
Sd hfru ti am? Gi6 trf tuyQt d6i cria s6 hiru ti x dugc x6c dfnh
Ciu 1: Thd nio td s6 hfru ti duong?
th6 ndo?
thua ctng co t6. tty thira cria: lf,y thria, mQt tich, mQt
2z Vi6t c6c c6ng thric: nhdn, chia hai lfly
Ciu
thuong.
thric tinh chAt cria ddy ti sO Uang
10 thric ld gi? Tinh chAt co b6n cria ti lQ thirc. Vitit c6ng
Cf,u 3: Ti
nhau.
hai mQt s61,h6ng 6m? Cho vi dp.
Cffu 4: Dinh nghia cdn b{c ctra
y v6i nhau? Tinh ch6t cria hai dai luqng ti lp thuen?
Cflu 5: Khi ndo thi hai d4i luqng vd x ti lQ thuan
chdt ctra hai luqng ti lQ nghich?
6: Khi ndo thi hai d4i luqng y vi x ti l0 nghich vcyi nhau? Tinh dai
Cffu
: :
y (a* dang nhu th6 nio?
hdm s6 y f(x) li gi? EO thi cria him s6 u 0) c6
Ciu 7: DO thi
hoc:
IV llinh
dinh lf vd hai g6c ddi dinh. Ph6t bidu dinh nghia hai duirng thing vu6ng
Cffu 1: Ph6t bidu dinh nghia,
g6c duong trung truc cira doan thing.
? Dinh nghia
vd hi€n nhQn bidt hai ducrng thing song song ? Dinh lf vd tinh chat hai
Cia 2z Ph6t bidu dinh ly d0u
thing song song .
duong
quan gifia vu6ng g6c vdi tinh song song.
tiOn dd dctit. Phdt bidu c6c dinh lf vd hQ tinh
Ciu 3: Ph6t bidu
ly vd ba dudng thing song song.
Dinh
gi6c g6c gi6c.
bidu dinh ty vd tdng ba g6c cria mQt tam ? Tinh chat ngoii cria tam
Cffu 4: Phdt
bing nhau cira hai tam gi6c vd c6c
Thd ndo ld hai tam gi6c bang nhau. Ph6t bidu ba truirng hqp
Cffu 5:
(Ve ghi gii
hQ qui hinh, thidt, kdt luQn)
-
B BAI TAP
V D4i sd
phdp tinh(Tinh hgp l! ndu c6 thA):
Dane,l; Thuc hiAn
(
I p?-.1)
c rc! +zs?,1
ut zz!.2- rg1 at [o.r-1] fl)
--47
---4s
(- (.s/
4) 4) 7 7 s
3
.(e) 1f-1-1)*1[--,
)
a>(z,+-+l e)
-!,+
1-rl 9-r, fl)
fi)
(5,,
(.
t- ) , s[ts oJ s( r

.-ly- t Ja 3J4s l2r?: ,(
h) rr.ir rv1^1 10.^6:0r 4tr n(zl*E!)
-Ilq
^( -qL*r!)+z!


9 6 63.102 3- 2) 6- 7 ) 2
12t1,
.-
*r .z;-Q^,t
o#.r(L*,2),+
il
Y),1^;-J-ux*ue]
[rs
,1*sf, +,2)
a ,
(-l (3.+-#)(+-+.;)
*
y,z:
Dang 2: Tim x,
Bni 1. Tim x bidt:
q
l*1
a) :2x=-5 at(*-l)fr*1)=o lr+!l-1=
l
l
4 3 4) 2) sl 2 10
,S-I=*
-223*-16=0
Ji*.,ffi)=*
,l*n*r
, Jm( s)28.
Ndm hgc 2018 2019
NQi dung 6n tQp HKl -
(x k) - 1l - 2l
h) - L)=25 ,l
=
[,r*l)=1 l2x lx
.
2) 25
bidt :
Biri 2: Tim z
!,
y
+y -z=-12 b) 3x *z=92
a) x:
=2y iJy=szvdx+
!:z=5:3:4vix
z=95 d) x: y: z=3:4:5vi 2x2+2y2-3*=-100
c) 2x- 3y=5zvix+y-
)c+y x-y
. r+l * v+2 z-l
-
1!--t--.-=:-----:
vdx+y-z=50 vdx.y=250
e)
il::----!-
34073
lopTBc6
Lop7Ac637 hgcsinh,
l. HgcsinhthOitOpTdEquy€ng6pdugcs5s6chnQpchothuviQn.
quy6n g6p
c6 40 hgc sinh, 16p 7D c6 36 hgc sinh. H6i m6i top du-o. c bao nhiOu
37 hgc sinh, 16p 7C
quyOn g6p ti lQ sO hgc sinh cria m5i top vd lop 7C g6p
quy6n s6ch ct. ni6t rang s6 s6ch dugc voi
hon lorp 7D ld8 quyOn s6ch.
nhiAu
ngiy,
cly, cdy tr€n ba c6ch ddng nhu nhau. DQi thf nhdt hoin thenh cOng vi0c trong 4
2. Ba dQi m6y
vd dQi thua ba hoan thenh trong 8 ngey. H6i m6i dQi c6 bao nhiOu
dQi hai hoin thinh trong 6 ngiy
dgi thf nhat c6 nhidu hcrn dqi thrl hai ld 2 mdy ciy vi cOng sudt c:iua cdc mdy li nhu
mdy ciy, bidt
nhau?
phii
nh6n hoan thanh mQt c6ng viQc trong 2l ngity. H6i tdng thOm bao nhiOu c6ng
3. Cho bi6t 56 c6ng
r a, , a t / Y A i:
-l
-
^
d6 trong 14 ngiy (ndng su6t m6i c6ng nh6n ld nhu nhau).
nhdn nfra d0 hoan thanh c6ng viQc
ti sd hai c4nh kd cfia n6 ld} : 5 vi diQn t(ch bing 40m2.
4. Tffi chu vi ctra mqt hinh chfi nhat, bidt
trdng dux,I79 cAy xung quanh tnr&rg. SO cay td 1 ftdng so v6i td Z Uing 6 : 11. So cay t6 1 tdng
5. Ba td hqc sinh
v6i td 3 bing 7 : 1O.H6i m6i td trohg dugc bao ntrieu cAy.
so
1)
sdgaocita
Cchrlag4o,ndunhflpviokhoAthCm
6. BakhoA,B, isdg4octran5.Xuat&khoBdi 1

7
7
kho c6 bao nhi0u tAn gao. Bidt rang
thi khi d6 sd gao 3 kho bang nhau. Tinh xem hic ddu & m5i
n6
A li 21 tan.
kho B chrla nhidu hon kho
- hdm sd:
Dane 4. Hd.m sd Dd thi
Cho him s6 y
Bii L:
=!*
5
a) VC dd thi him sd
b) Tim gi6 tri cria him sd tai x -1 x
= ; =0
didm trOn dd thi c6 tung dQ 11 4. X6c dinh tga dQ didm d6.
c) Tim
2: Cho him s6 y
Bii
=--2*
5
him s6
a) VE dd thi
(-5 (0
thuoc d6 thi him sd d6: M N 3); P .
b) Trong c6c didm sau dAy thi didm ndo ;2); ; ;
tl -f
ll
5
Bii 3: Didm B (2;-1) thuQc dd thi him s6 ax.
Y =
a)Xdc dinh a
b) Ve dd thi him sd vDa tim duo.c
cao:
Dans 5: Cdc bdi tud.n ndng
BiiI: Tim GTLN, GTNN.
1) Tim gi6 tri nh6 nhat cta bidu thrlc:
-5 B=x2+3ly- 2l+l
A=312x- 1l
Tim gi6 tri l6n nhdt cria bidu thrlc:
2)
D=5 -(2x-l)2
C= 10 -5lx-21
Bii 2: So sdnh:
2
2019
Ndm hgc 2018 -
6n tQp HKl
NQi dung
c) 9920 vI 999910
32oo
a) Z,o, vd
yd.Z3r +23 +... + zt0oydztol
d) S= l+2+22
b)32r
CMR:
Bii 3; Cho tt lQ thitc:
+: +
bd
lc2
+3cd
+3d 7o +3ab
5a +3b 5c
,
-,,
a) -

tr-, rF
salb= rro2
-gP
-Bb-
: :bd.
di0u kiQn b2 ac; c2
b6n s5 a, b, c, d thoi mdn
Bii 4: Cho
chrmgminh: 1^*4*cr=9
b
b+c+d
IU llinh hoc
(AD, thuQc nta mit
song song vdi BC ldy AD BC BC cing
AABC (3 g6c nhqn).TrOn tia Ax
Bii L: Cho =
Chung minh:
phing bd li ducrng thing AB).
a) AADC ACBA
=
g6c BCD
b) G6c BAD
=
c) AB
llDC
:300.
A c6 g6c B
Bii 2:. Cho AABC vu6ng t4i
a) Tinh sd do g6c C.
:
CM CA.
D. Trdn canh CB l6y di6m M sao cho
VC tia phdn gi6c cria g6c C cat cqnh AB tai
b)
minh: AACD: AMCD.
Chrmg
th6ng song song vcvi CD c6t xy o K.
xy vu6ng g6c CA. Ttr A k6 duong
c) C vE dulng thdng
Qua
minh:AK = CD.
Chrmg
Tinh sO do g6c AKC.
d)
vi B, trOn tia Oy tay didm C vi D sao cho
g5c TrCn tia Ox ldy hai didm A
Bii 3:. Cho xOy.
OC; AB CD. Chung minh:
OA
=
=
a) BC=AD
ACID
vi AD. Chrrng minh rang: AAIB
b) Gqi I ti giao cira BC
=
gi6c g6c xOy
c) OI ti phAn cira
g6c v6i BD
d) OI vu6ng
lay didm M sao
F ld trung didm AB. TrOn tia ddi cira EB
gi6cABC. Gqi Eld trung didm AC
Bii 4: Cho tam ,
cho FC. Chung minh:
tia ddi ctra FC ldy didm N sao FN
cho EM MB. TrOn =
=
AAME ACBE
a)
=
BC vi AM
b) AM //BC
=
c)AM=AN
d)M,A,Nthinghdng
F thu6c tia
(AB gidc LifyEthuQc AC sao cho AB AE; Ldy
gi6c ABC < AC) kB phan AD.
Bii 5: Cho tam =
BF EC. Chung minh:
ddi cira tia BA sao cho
=
a) AABD AAED
=
b)DF=DC
c)F,D,Ethfnghlng
d)ADTFC
tia ddi cira
BC N li trung didm cira AC. Ldy E thuQc
gi6c ABC. Ggi M li trung didm cira
Bii 6: Cho tam ;
minh:
sao cho NM Chung
NM
=NE.
MC suy ra AE MC
a) AE //
=
AABM
b) AMEA
=
c) MN AB
ll

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